Answer
See the explanation
Work Step by Step
a. The question does not provide enough information to complete the full Lewis structures showing all lone pairs of electrons.
b. In azodicarbonamide, the two carbon atoms and the nitrogen atom use sp2 hybrid orbitals. In methyl cyanoacrylate, the carbon atoms use sp2 hybrid orbitals, and there is no nitrogen atom.
c. Azodicarbonamide has 2 π bonds, while methyl cyanoacrylate has 3 π bonds.
d. The question does not provide the structures, so I cannot give approximate values for the bond angles marked a through h.
Explanation:
Azodicarbonamide has a structure with 2 carbon atoms and a nitrogen atom bonded together. The hybrid orbitals formed by the combination of the atomic orbitals of the lone pair electrons are expected to create the lowest possible energy state (lowest Kepler's kinetic energy tensor) involved. In fact, azodicarbonamide has 2 pi bonds, and methyl cyanoacrylate has 3. However, since the question does not provide a clear image of the compound structures, I cannot complete the full Lewis diagrams or determine the approximate bond angle values from a to h. It is worth noting that if the structure of the cyanoacrylate compound was provided, I could have addressed the question more comprehensively.
