Answer
See the explanation
Work Step by Step
Let's predict the molecular structures and bond angles for the given compounds.
a. $XeCl_{2}$:
- Molecular structure: Linear
- Bond angles: 180°
Explanation:
Xenon (Xe) is a group 18 element, and it has an octet configuration. In the $XeCl_{2}$ molecule, the xenon atom forms two covalent bonds with two chlorine atoms. The molecular structure is linear, with a bond angle of 180° between the two Xe-Cl bonds.
b. $ICl_{3}$:
- Molecular structure: T-shaped
- Bond angles: 90°
Explanation:
Iodine (I) is a group 17 element, and it has an octet configuration. In the $ICl_{3}$ molecule, the iodine atom forms three covalent bonds with three chlorine atoms. The molecular structure is T-shaped, with a bond angle of 120° between the three Cl-I-Cl bonds.
c. $TeF_{4}$:
- Molecular structure: Square planar
- Bond angles: 90°
Explanation:
Tellurium (Te) is a group 16 element, and it has an octet configuration. In the $TeF_{4}$ molecule, the tellurium atom forms four covalent bonds with four fluorine atoms. The molecular structure is square planar, with a bond angle of 90° between the F-Te-F bonds.
d. $PCl_{5}$:
- Molecular structure: Trigonal bipyramidal
- Bond angles: 120° (equatorial), 90° (axial)
Explanation:
Phosphorus (P) is a group 15 element, and it has an octet configuration. In the $PCl_{5}$ molecule, the phosphorus atom forms five covalent bonds with five chlorine atoms. The molecular structure is trigonal bipyramidal, with a bond angle of 120° between the equatorial Cl-P-Cl bonds and 90° between the axial Cl-P-Cl bonds.
