Answer
Square planar: $XeF_4$
Square pyramidal: $ClF_5$
Work Step by Step
Let’s analyze the octahedral derivatives shown (square planar and square pyramidal) and match them to the given compounds/ions.
Step 1: Understand the geometries
1. Square planar
- Derived from an octahedral electron-pair geometry (6 electron pairs).
- 2 lone pairs opposite each other → 4 bonds in a plane.
- Example bond angles: 90° and 180° in the plane.
2. Square pyramidal
- Also derived from octahedral geometry (6 electron pairs).
- 1 lone pair, 5 bonds → 4 in a plane, 1 above → pyramid.
- Bond angles slightly < 90° or 180° due to lone pair repulsion.
Step 2: Analyze the given molecules/ions
$Br_3$: rigonal bipyramidal (AX₃E₃ → T-shaped) - Not square planar/pyramidal
$CIF_3$: Trigonal bipyramidal (AX₃E₂) - T-shaped, not square planar/pyramidal
$XeF_4$: Octahedral - Square planar
$SF_4$: Trigonal bipyramidal (AX₄E) - See-saw, not square planar/pyramidal
$PF_5$: Trigonal bipyramidal - Not square planar/pyramidal
$CIF_5$: Octahedral (AX₅E) - Square pyramidal
$SF_6$: Octahedral (AX₆) - Octahedral, not square planar/pyramidal
We got:
Square planar: $XeF_4$
Square pyramidal: $ClF_5$
