Answer
See explanation
Work Step by Step
To write the Lewis structure for borazine (B3N3H6), we need to follow these steps:
1. Determine the number of valence electrons for each element:
- Boron (B) has 3 valence electrons.
- Nitrogen (N) has 5 valence electrons.
- Hydrogen (H) has 1 valence electron.
2. Construct the skeletal structure:
- Borazine has a six-membered ring with alternating boron and nitrogen atoms.
- Each boron and nitrogen atom is bonded to one hydrogen atom.
3. Draw the Lewis structure:
- The Lewis structure for borazine (B3N3H6) is as follows:
```
H
/
B-N
| |
B-N
/ \
H H
```
The Lewis structure for borazine (B3N3H6) shows a six-membered ring with alternating boron and nitrogen atoms. Each boron and nitrogen atom is bonded to one hydrogen atom, resulting in a total of six hydrogen atoms.
The key features of the borazine structure are:
- The six-membered ring consists of three boron atoms and three nitrogen atoms, arranged in an alternating pattern.
- Each boron and nitrogen atom has one hydrogen atom bonded to it.
- The structure resembles the structure of benzene (C6H6), which is why borazine is often called "inorganic benzene."
- The alternating boron and nitrogen atoms in the ring create a delocalized π-system, similar to the delocalized π-system in benzene.
