Chemistry: Atoms First (2nd Edition)

Published by Cengage Learning
ISBN 10: 1305079248
ISBN 13: 978-1-30507-924-3

Chapter 3 - Exercises - Page 150d: 82

Answer

See the explanation

Work Step by Step

a. Lewis Structures: 1. $POCl_{3}$: - The central atom is P, and it is surrounded by 3 Cl atoms and 1 O atom. - P has 5 valence electrons, each Cl has 7 valence electrons, and O has 6 valence electrons. - To satisfy the octet rule, P needs to form 4 bonds, and each Cl and O need to form 2 bonds. - The Lewis structure is: ${P=O-Cl-Cl-Cl}$ 2. $SO_{4}^{2-}$: - The central atom is S, and it is surrounded by 4 O atoms. - S has 6 valence electrons, and each O has 6 valence electrons. - To satisfy the octet rule, S needs to form 4 bonds, and each O needs to form 2 bonds. - The Lewis structure is: ${O=S(=O)=O}$ 3. $XeO_{4}$: - The central atom is Xe, and it is surrounded by 4 O atoms. - Xe has 8 valence electrons, and each O has 6 valence electrons. - To satisfy the octet rule, Xe needs to form 4 bonds, and each O needs to form 2 bonds. - The Lewis structure is: ${O=Xe(=O)=O}$ 4. $PO_{4}^{3-}$: - The central atom is P, and it is surrounded by 4 O atoms. - P has 5 valence electrons, and each O has 6 valence electrons. - To satisfy the octet rule, P needs to form 4 bonds, and each O needs to form 2 bonds. - The Lewis structure is: ${O=P(=O)(-O)(-O)}$ 5. $ClO_{4}^{-}$: - The central atom is Cl, and it is surrounded by 4 O atoms. - Cl has 7 valence electrons, and each O has 6 valence electrons. - To satisfy the octet rule, Cl needs to form 4 bonds, and each O needs to form 2 bonds. - The Lewis structure is: ${O=Cl(=O)(-O)(-O)}$ b. Lewis Structures: 1. $NF_{3}$: - The central atom is N, and it is surrounded by 3 F atoms. - N has 5 valence electrons, and each F has 7 valence electrons. - To satisfy the octet rule, N needs to form 3 bonds, and each F needs to form 1 bond. - The Lewis structure is: ${F-N-F}$ 2. $SO_{3}^{2-}$: - The central atom is S, and it is surrounded by 3 O atoms. - S has 6 valence electrons, and each O has 6 valence electrons. - To satisfy the octet rule, S needs to form 3 bonds, and each O needs to form 2 bonds. - The Lewis structure is: ${O=S(=O)-O}$ 3. $PO_{3}^{3-}$: - The central atom is P, and it is surrounded by 3 O atoms. - P has 5 valence electrons, and each O has 6 valence electrons. - To satisfy the octet rule, P needs to form 3 bonds, and each O needs to form 2 bonds. - The Lewis structure is: ${O=P(-O)(-O)}$ 4. $ClO_{3}^{-}$: - The central atom is Cl, and it is surrounded by 3 O atoms. - Cl has 7 valence electrons, and each O has 6 valence electrons. - To satisfy the octet rule, Cl needs to form 3 bonds, and each O needs
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