Chemistry: Atoms First (2nd Edition)

Published by Cengage Learning
ISBN 10: 1305079248
ISBN 13: 978-1-30507-924-3

Chapter 3 - Additional Exercises - Page 150g: 127

Answer

See the explanation

Work Step by Step

a. NaBr or $NaBr_{2}$ The more energetically stable compound would be NaBr. Explanation: NaBr is a neutral ionic compound, where the sodium (Na) atom has a +1 oxidation state and the bromine (Br) atom has a -1 oxidation state. This results in a stable ionic bond between the two atoms, leading to a lower energy state. On the other hand, $NaBr_{2}$ would be an unstable compound, as it would have a bromine atom with a -2 oxidation state, which is highly unfavorable. The presence of two bromine atoms bonded to a single sodium atom would create a high-energy, unstable configuration. b. $ClO_{4}$ or $ClO_{4}^{-}$ The more energetically stable compound would be $ClO_{4}^{-}$ (perchlorate ion). Explanation: The perchlorate ion, $ClO_{4}^{-}$, is a stable and well-known anion. The chlorine atom has a +7 oxidation state, and the four oxygen atoms provide a stable, tetrahedral arrangement around the chlorine atom. In contrast, $ClO_{4}$ would be an unstable neutral species, as the chlorine atom would have a +8 oxidation state, which is highly unfavorable. The neutral $ClO_{4}$ compound would have a higher energy configuration compared to the stable perchlorate ion. c. $SO_{4}$ or $XeO_{4}$ The more energetically stable compound would be $XeO_{4}$ Explanation: The Lewis structure cannot be drawn so that it obeys the octet rule for $SO_4$ (30 electrons) unlike $XeO_4$ d. $OF_{4}$ or $SeF_{4}$ The more energetically stable compound would be $SeF_{4}$ (selenium tetrafluoride). Explanation: Selenium tetrafluoride, $SeF_{4}$, is a stable and known compound in chemistry. The selenium atom has a +4 oxidation state, and the four fluorine atoms form a stable, square planar arrangement around the selenium atom. In contrast, $OF_{4}$ (oxygen tetrafluoride) would be an unstable neutral compound. Oxygen typically forms stable compounds with a maximum of two bonds, and the formation of four bonds with fluorine atoms is highly unfavorable. The $OF_{4}$ compound would have a higher energy configuration compared to the stable selenium tetrafluoride.
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