Answer
See the explanation
Work Step by Step
The ground state of arsenic, As, has 33
electrons:
$1s^22s^22p^63s^23p^64s^23d^{10}4p^3$
- The number of electrons with \( \ell=1 \) is the sum of all electrons in $p$ orbitals:
$6+6+3=15$
- The number of electrons with \( m_{\ell}=0 \): $m_l=0$ occurs in every orbital type; each orbital with $m_l=0$ can hold 2 electrons:
$s$ orbitals: $4\times 2=8$ electrons
$p$ orbitals: $2+2+1=5$ electrons
$d$ orbitals: $1\times 2=2$ electrons
Total: $8+5+2=15$ electrons
- The number of electrons with \( m_{\ell}=+1 \): it applies to $p$ and $d$ orbitals
$p$ orbitals: $2+2+1=5$ electrons
$d$ orbitals: $1\times 2=2$ electrons
Total: $5+2=7$ electrons
