## Chemistry: Atoms First (2nd Edition)

$H_2SO_3(aq) + H_2O(l) \lt -- \gt HS{O_3}^-(aq) + H_3O^+(aq)$ $HS{O_3}^-(aq) + H_2O(l) \lt -- \gt S{O_3}^{2-}(aq) + H_3O^+(aq)$
1. Write the reaction where $H_2SO_3$ behaves as an acid in water. $H_2SO_3(aq) + H_2O(l) \lt -- \gt HS{O_3}^-(aq) + H_3O^+(aq)$ - It will donate one proton to the water molecule, producing $H_3O^+$. 2. Write the reaction where the conjugate base acts as an acid: $HS{O_3}^-(aq) + H_2O(l) \lt -- \gt S{O_3}^{2-}(aq) + H_3O^+(aq)$ - Since $S{O_3}^{2-}$ can't donate protons, the dissociation stops there.