Answer
$N{H_3}$, $Cl{O_2}^-$, $H_2O$, $ClO_4^-$
Work Step by Step
Using the table 13-2, from page 531, and knowing that:
Strong acids: $K_a > 1$
$H_3O^+$: $K_a = 1.0$
Identify each acid ka value for the conjugate acids of these compounds:
$HClO_2$: $K_a = 1.2 \times 10^{-2}$
$H_3O^+$: $K_a = 1.0$
$N{H_4}^+$: $K_a = 5.6 \times 10^{-10}$
$HClO_4$: $K_a > 1$
- Ordering in decreasing order, we obtain:
$HClO_4, H_3O^+, HClO_2, N{H_4}^+$
- The stronger the acid, the weaker its conjugate base, and vice versa.
Therefore: the bases in decreasing order are:
$NH_3, ClO_2^-, H_2O, ClO_4^-$
- We've inverted the previous order.
