Chemistry: Atoms First (2nd Edition)

Published by Cengage Learning
ISBN 10: 1305079248
ISBN 13: 978-1-30507-924-3

Chapter 1 - Exercises - Page 51c: 37

Answer

Density of nucleus = 3 $\times 10^{15}$ g/cm$^{3}$ Density of atom = 0.4 g/cm$^{3}$

Work Step by Step

Mass of proton = $1.673 \times 10^{-24}$ g Radius of nucleus = $ 10^{-13}/2=5\times 10^{-14}$ cm Volume of nucleus = $\frac{4}{3}\times3.14\times( 5\times 10^{-14})^{3}$ = 5 $\times 10^{-40}$ cm$^{3}$ Density of nucleus = $\frac{1.673\times 10^{-24}}{5\times 10^{-40}}$ = 3 $\times 10^{15}$ g/cm$^{3}$ Mass of atom = $1.673 \times 10^{-24}+9\times 10^{-28}$ g Radius of atom = $ 10^{-8}$cm Volume of atom = $\frac{4}{3}\times3.14\times(1\times10^{-8})^{3}$ = 4 $\times 10^{-24}$ cm$^{3}$ Density of atom = $\frac{1.673 \times 10^{-24}+9\times 10^{-28}}{4\times 10^{-24}}$ = 0.4 g/cm$^{3}$
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