Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Let's Review: The Tools of Quantitative Chemistry - Study Questions - Page 43c: 39


$50 \ mg$

Work Step by Step

We are given the density and the volume ($V=0.50\ mL,\ \rho=1.0\ g/mL$), so the total mass is: $m=0.50\times1.0 = 0.50\ g$ Since the solution contains 10% by mass of the compound: $m_c=0.50\times0.10=0.050\ g$ $0.050\ g \times \dfrac{1\ mg}{1\times10^{-3}\ g}=50 \ mg$
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