Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 9 Bonding and Molecular Structure: Orbital Hybridization and Molecular Orbitals - Study Questions - Page 369d: 48


See the answer below.

Work Step by Step

a,b) Carbons in the aromatic ring are $sp^2$ hybridized because they make a double bond each, thus angle A is 120°. The other carbons and the nitrogen are $sp^3$ hybridized because they make single bonds only, thus angles B and C are approximately 109°. c) There are 25 $\sigma$ bonds and 3 $\pi$ bonds. d) This molecule is polar because it has asymmetrical polar bonds (CN and NH). e) The proton attaches itself to the nitrogen because it's the most electronegative atom in the molecule and has a lone electron pair, both displayed in the potential surface by the red spot around it.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.