Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 9 Bonding and Molecular Structure: Orbital Hybridization and Molecular Orbitals - Study Questions - Page 369c: 41

Answer

See the answer below.

Work Step by Step

a) The C=O bond, because it has the biggest difference in electronegativity between the ligands. b) There are 18 $\sigma$ bonds and 5 $\pi$ bonds. c) Yes, representing by [Ar] the aromatic ring: $\begin{smallmatrix} [Ar]&-&C&=&C&-&C&=&O&&&[Ar]&-&C&=&C&-&H\\ &&|&&|&&|&&&&&&&|&&|&&&&&\\ &&H&&H&&H&&&&&&&H&&HC&=&O&&&\\ \end{smallmatrix}$ d,e) All carbons are $sp^2$ hybridized because they make a double bond each, thus the angles 1, 2 and 3 are 120°.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.