Answer
See the answer below.
Work Step by Step
a) The C=O bond, because it has the biggest difference in electronegativity between the ligands.
b) There are 18 $\sigma$ bonds and 5 $\pi$ bonds.
c) Yes, representing by [Ar] the aromatic ring:
$\begin{smallmatrix}
[Ar]&-&C&=&C&-&C&=&O&&&[Ar]&-&C&=&C&-&H\\
&&|&&|&&|&&&&&&&|&&|&&&&&\\
&&H&&H&&H&&&&&&&H&&HC&=&O&&&\\
\end{smallmatrix}$
d,e) All carbons are $sp^2$ hybridized because they make a double bond each, thus the angles 1, 2 and 3 are 120°.
