#### Answer

C

#### Work Step by Step

$NO_2^-$ is making a $\pi$ bond, thus it's in a $sp^2$ hybridization.

Published by
Cengage Learning

ISBN 10:
1133949649

ISBN 13:
978-1-13394-964-0

C

$NO_2^-$ is making a $\pi$ bond, thus it's in a $sp^2$ hybridization.

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