Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 8 Bonding and Molecular Structure - Study Questions - Page 337d: 73


See the answer below.

Work Step by Step

a) Bonds broken: 3 O=O, 6 C-H, 2 O-H, 2 O-C Bonds formed: 4 C=O, 8 O-H (net: 6) Enthalpy of reaction: $3×498+6×413+2×358-4×803-6×463=-1302\ kJ/mol$ b) Enthalpies of formation: $CH_3OH(g): -201, CO_2(g): -393.509, H_2O(g): -241.83\ kJ/mol$ Enthalpy of reaction: $4×-241.83+2×-393.509-2×-201=-1352.3\ kJ/mol$ Both values are reasonably close to each other.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.