Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 8 Bonding and Molecular Structure - Study Questions: 35


See the answer below.

Work Step by Step

a) Valence electrons C: 4, H: 1, O: 6, N:5 Bicarbonate: $3×6+1+4+1=24$ Nitric acid: $1+5+3×6=24$ They are isoelectronic. b) Two ressonance structures each, alternating the O= with the O- group. c) The nitrogen in nitric acid has a formal charge of +1, the oxygen making a single bond only in both cases has a formal charge of -1, but due to ressonance, they have a -1/2 charge along with the one making a double bond. d) It's harder to remove/easier to add a $H^+$ from/to a negatively charged anion like bicarbonate than nitric acid, therefore it's more acidic.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.