## Chemistry and Chemical Reactivity (9th Edition)

a) $\psi=\dfrac 1{\sqrt{\pi.(52.9\times10^{-12}\ m)^3}}.e^{-\frac{r=a_0}{a_0}}$ $\psi=5.39\times10^{14}\ m^{-3/2}$ $P=4\pi.(52.9\times10^{-12}\ m)^2\times(5.39\times10^{14}\ m^{-3/2})^2\times1.0\times10^{-12}\ m$ $P=0.01\approx 1\%$ b) Similarly as in a: $0.50 a_0: P=6.95\times10^{-3}$ $4a_0: P=4.06\times10^{-4}$ The decline in probability away from the most probable distance is in accord with figure 6.12b.