## Chemistry and Chemical Reactivity (9th Edition)

$\Delta E=-Z^2Rhc(1/n_f^2-1/n_i^2)$ With $Z=2, Rhc=2.179\times10^{-18}\ J$ $n_f\rightarrow+\infty, n_i=1$ $\Delta E=8.72\times10^{-18}\ J$ This value is bigger than hydrogen's ionization energy by a factor of $Z^2=4$.