# Chapter 6 The Structure of Atoms - Study Questions - Page 247c: 56

#### Work Step by Step

$c=\lambda\times\nu$ $\nu=2.998\times10^8\ m/s\div 375 \times10^{-9}\ m=7.995\times10^{14}\ 1/s$ Per photon: $E=h\times\nu$ $E=6.626\times10^{-34}\ J.s\times 7.995\times10^{14}\ 1/s=5.30\times10^{-19}\ J$ Per mole: $E=5.30\times10^{-19}\ J\times6.022\times10^{23}\ 1/mol=319.0\ kJ/mol$

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