Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 6 The Structure of Atoms - Study Questions - Page 247b: 25


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Work Step by Step

From De Broglie's equation: $\lambda=\frac h{m.v}$ $\lambda=6.626\times20^{-34}\ J.s\times 1\ (kg.m^2/s^2)/J\div (0.046\ kg\times 30\ m/s)$ $\lambda=4.80\times 10^{-34}\ m=4.80\times 10^{-25}\ nm$ For the given wavelength: $v=6.626\times20^{-34}\ J.s\times 1\ (kg.m^2/s^2)/J\div (0.046\ kg\times 5.6\times10^{-12}\ m)$ $v=2.57\times10^{-21}\ m/s$
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