Chapter 6 The Structure of Atoms - Study Questions - Page 247b: 24

$\lambda=5.595\times 10^{-12}\ m$

From De Broglie's equation: $\lambda=\frac h{m.v}$ $\lambda=6.626\times20^{-34}\ J.s\times 1\ (kg.m^2/s^2)/J\div (9.11\times 10^{-31}\ kg\times 1.3\times 10^8\ m/s)$ $\lambda=5.595\times 10^{-12}\ m$