## Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning

# Chapter 5 Principles of Chemical Reactivity: Energy and Chemical Reactions - Study Questions - Page 217j: 115

#### Answer

See the answer below.

#### Work Step by Step

a) From the diagram it's methane (955.1 kJ vs 676.1 kJ) b) Methane: $-955.1\ kJ/mol\times16.04\ g/mol=-59.55\ kJ/g$ Methanol: $-676.1\ kJ/mol\times 32.04\ g/mol=-21.10\ kJ/g$ It's methane again. c) From the diagram: $-955.1--676.1=-279.0\ kJ/mol$ d) From the diagram, cancelling the excess oxygen: $CH_4(g)+1/2\ O_2(g)\rightarrow CH_3OH(l)$

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