Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 4 Stoichiometry: Quantitative Information about Chemical Reactions - Study Questions - Page 179b: 16


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Work Step by Step

Number of moles of the reactants: Aluminum: $2.70\ g\div 26.983 g/mol=0.100\ mol$ Chlorine: $4.05\ g\div 70.906\ g/mol=0.057\ mol$ Ratio: $0.057/0.100=0.57$ Chlorine is the limiting reactant. From stoichiometry: $0.057\ mol\times 1_{AlCl_3}/3_{Cl_2} \times 133.34\ g/mol\ AlCl_3=2.54\ g\ AlCl_3$ Aluminum reacted: $0.057\ mol\times 2_{Al}/3_{Cl_2} \times 26.982\ g/mol\ Al=1.03\ g\ Al$ Remaining: $2.70-1.03=1.67\ g\ Al$ $\begin{smallmatrix} &2\ Al&3\ Cl_2&\rightarrow&2\ AlCl_3\\ Initial &0.100&0.057&&0\\ Reacted&-0.038&-0.057&&+0.038\\ Final&0.062&0&&0.038\\ \end{smallmatrix}$
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