Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 4 Stoichiometry: Quantitative Information about Chemical Reactions - Study Questions - Page 179b: 15


Methane is the limiting reactant. $375\ g\ H_2$ $1392.5\ g\ H_2O$

Work Step by Step

Number of moles of the reactants: Methane: $995\ g\div 16.04\ g/mol=62.03\ mol$ Water: $2510\ g\div 18.015\ g/mol=139.33\ mol$ Ratio: $139.33/62.03=2.25$ Methane is the limiting reactant. From stoichiometry: $62.03\ mol\times 3_{H_2}/1_{CH_4} \times 2.016\ g/mol\ H_2=375\ g\ H_2$ Water reacted: $62.03\ mol\times 1_{H_2O}/1_{CH_4} \times 18.015\ g/mol\ H_2O=1117.5\ g\ H_2O$ Remaining: $2510-1117.5=1392.5\ g\ H_2O$
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