## Chemistry and Chemical Reactivity (9th Edition)

$C_8H_{14}O_4N_4Ni$
In 100 g of the solid: Ni:$20.315\ g/58.6934\ g/mol=0.346\ mol$ C: $33.258\ g/12.011\ g/mol=2.77\ mol$ H: $4.884\ g/1.008\ g/mol=4.84\ mol$ O: $22.151\ g/15.999\ g/mol=1.38\ mol$ N: $19.392\ g/14.007\ g/mol=1.38\ mol$ Dividing by the smallest value: Ni:$0.346/0.346=1.00$ C:$2.77/0.346=8.00$ H:$4.84/0.346=14.0$ O,N:$1.38/0.346=4.00$ Hence the empirical formula is: $C_8H_{14}O_4N_4Ni$