Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 3 Chemical Reactions - Study Questions - Page 137e: 68


See answer below.

Work Step by Step

$HNO_3$: oxidizing agent in a reaction where $H_2$ is released because the oxidation number of H decreases (+1 to 0) or in a reaction where $NO_3^-$ is converted to $NO_2^-$ because the oxidation number of N decreases (+5 to +3). $Na$: reducing agent, the ionization to $Na^+$ would increase the oxidation number of Na (0 to +1). $Cl_2$: oxidizing agent, the ionization to $Cl^-$ or a covalent bond where Cl is the most electronegative would decrease the oxidation number of Cl (0 to -1). It can be a reducing agent in a reaction where a $ClF$ is a product. $O_2$: oxidizing agent, the most common oxidation number of O is -2, or even -1 in peroxides, so its oxidation number would decrease in most reactions. It can be a reducing agent if a product of the reaction is $OF_2$ $KMnO_4$: oxidizing agent, common oxidation numbers for Mn are +2 or +4 and 0 in the metal, so it would decrease from +7 in $KMnO_4$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.