Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 3 Chemical Reactions - Study Questions - Page 137e: 67


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Work Step by Step

$NaBr$ was oxidized because the oxidation number of Br increases from -1 to 0 in $Br_2$, thus it's the reducing agent. $Cl_2$ was reduced because the oxidation number of Cl decreases from 0 to -1 in $NaCl$, thus it's the oxidizing agent.
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