# Chapter 3 Chemical Reactions - Study Questions - Page 137d: 49

#### Work Step by Step

a) $C_2H_4$ is oxidized because carbon's oxidation number goes from -2 to +4, in $CO_2$, thus it's the reducing agent. $O_2$ is reduced because oxygen's oxidation number goes from 0 to -2, in water and $CO_2$, thus it's the oxidizing agent. b) $Si$ is oxidized because silicon's oxidation number goes from 0 to +4, in $SiCl_4$, thus it's the reducing agent. $Cl_2$ is reduced because chlorine's oxidation number goes from 0 to -1, in $SiCl_4$, thus it's the oxidizing agent.

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