Answer
Y:$13.37\%$
Ba: $41.30\%$
Cu: $28.66\%$
O: $16.67\%$
Work Step by Step
Molar mass of $YBa_2Cu_3O_{6.93}$
$M= 88.90585+137.327\times2+63.546\times3+15.9994\times6.93$
$M=665.07\ g/mol$
Y:$88.90585/M=13.37\%$
Ba: $137.327\times2/M=41.30\%$
Cu: $63.546\times3/M=28.66\%$
O: $15.9994\times6.93=16.67\%$