Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 25 Nuclear Chemistry - Study Questions - Page 1007b: 30


$0.17\,\mu g$

Work Step by Step

Time elapsed=10.8 days=$\frac{10.8\,days}{2.69\,days}$ half-lives= 4.01 half-lives. The amount of gold-198 has decreased to $(\frac{1}{2})^{4.01}$ of the original amount. The amount of gold-198 remaining$=2.8\,\mu g\times(\frac{1}{2})^{4.01}=0.17\,\mu g$
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