Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 2 Atoms, Molecules, and Ions - Study Questions: 123

Answer

$Fe_2(CO)_9$

Work Step by Step

Atomic weight $Fe: 55.845\ g/mol$ Molar mass of the compound, assuming x = 1: $55.845\ \div \frac{30.70}{100}=181.9\ g/mol$ Molar mass of CO $28.01\ g/mol$ $55.845+y\times28.01=181.9\rightarrow y=4.50$ Multiplying by 2 to make x and y integers: Empirical formula $Fe_2(CO)_9$
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