Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 2 Atoms, Molecules, and Ions - Study Questions - Page 95e: 96



Work Step by Step

Atomic weight $Ge: 72.630 g/mol$ Molar mass: $Cl_2: 70.91\ g/mol$ Mass of Ge: 1.25 g Mass of the product: 3.69 g Mass of $Cl_2$: 3.69- 1.25= 2.44 g Number of mols: Ge: $1.25/72.630=0.0172\ mol$ $Cl_2$: $2.44/70.91=0.0344\ mol\ Cl_2 = 0.0688\ mol\ Cl$ Ratio of the number of moles of Cl by Ge: $0.0688/0.0172=4.00 = y/x$ From the data given, only the ratio y/x can be determined. Assuming x=1: Product's molecular formula: $GeCl_4$
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