Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 2 Atoms, Molecules, and Ions - Study Questions - Page 95c: 55



Work Step by Step

The electrostactic attraction force, by Coulomb's Law is $F=-k\frac{q_1q_2}{d^2}$, The distance, in this case, is the sum of the ionic radii: $NaF$: $116\ pm + 119\ pm = 235\ pm $ $NaI$: $116\ pm + 206\ pm = 322\ pm $ Since in both cases one electron is exchanged, in NaF the force of attraction is bigger because the distance between the charges is smaller.
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