Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 2 Atoms, Molecules, and Ions - Study Questions - Page 95b: 41


$Ba^{2+}$, $Br^-$ $BaBr_2$

Work Step by Step

Barium (Ba) is from group 2A, so it should lose two electrons: $Ba^{2+}$ Bromine (Br) is from group 7A, so it should lose one electron: $Br^-$ The ionic compound formed by the two would be $BaBr_2$
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