Chapter 17 Principles of Chemical Reactivity: Other Aspects of Aqueous Equilibria - Study Questions - Page 677a: 20

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Work Step by Step

$K_a=[H_3O^+][NH_3]/[NH_4^+]$ Applying the -log to both sides $pKa=pH-log([NH_3]/[NH_4^+])$ $[NH_3]/[NH_4^+]=1.77$ Mix them with a ratio of 1.77 mol of ammonia per mol of ammonium.

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