Answer
$pH=2.57$
Work Step by Step
Initial molarity: $94.5/1000\ g\div 94.50\ g/mol\div 125/1000\ L=0.008\ M$
$K_a=x\cdot x/(0.008-x)$
$x=[H_3O^+]=0.0027\ M$
$pH=2.57$
Chemistry and Chemical Reactivity (9th Edition)
by Kotz, John C.; Treichel, Paul M.; Townsend, John R.; Treichel, David A.
Published by
Cengage Learning
ISBN 10:
1133949649
ISBN 13:
978-1-13394-964-0
Chapter 16 Principles of Chemical Reactivity: The Chemistry of Acids and Bases - Study Questions - Page 629f: 96
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