Answer
(a)
- Products: ${NO_3}^- and$ $H_3O^+$
Acid: $HNO_3$; Conjugate base: ${NO_3}^-$;
Base: $H_2O$; Conjugate acid: $H_3O^+$;
(b)
- Products: ${SO_4}^{2-}$ and $H_3O^+$
Acid: $H{SO_4}^{-}$; Conjugate base: ${SO_4}^{2-}$
Base: $H_2O$; Conjugate acid: $H_3O^+$
(c)
- Products: $H_2O$ and $HF$.
Acid: $H_3O^+$; Conjugate base: $H_2O$
Base: $F^-$; Conjugate acid: $HF$
Work Step by Step
1. Identify the acid and the base.
- The acid is the reactant that can donate one of its protons ($H^+$), and the base is the reactant that can receive this proton.
2. Remove one proton from the acid.
- Remove 1 hydrogen, and subtract 1 from the charge.
- It is one of the products, the conjugate base.
3. Add one proton to the base.
- Add 1 hydrogen, and sum 1 to the charge.
- It is the other product, the conjugate acid.
