Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 15 Principles of Chemical Reactivity: Equilibria - Study Questions - Page 583b: 14


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Work Step by Step

$n_{cH,Reacted}=x, [cH]_{Equil}=(0.045-x)/V$ $n_{cP,Formed}=x, [cP]_{Equil}=x/V$ $K=[cP]/[cH]\rightarrow 0.12=x/(0.045-x)$ $x=0.0048\ mol$ At equilibrium: $[cH]=(0.045-0.0048)/2.8=0.014\ M, [cP]=0.0048/2.8=0.0017\ M$
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