Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 14 Chemical Kinetics: The Rates of Chemical Reactions - Study Questions - Page 553g: 73


See the answer below.

Work Step by Step

a) For second-order reactions: $1/C-1/C_0=kt$ $1/0.100\ M-1/0.250\ M=k\times 1.76\ min$ $k=3.41\ L/mol.min$ b) In the first case $r=-\Delta [NO_2]/\Delta t$, now $r'=\Delta[O_2]/\Delta t=-1/2\dot{}\Delta [NO_2]/\Delta t=1/2\dot{}r$ So the new constant is $k'=1/2\dot{}k$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.