Chemistry and Chemical Reactivity (9th Edition)

The number of moles of solvent: $955g\div18.015\ g/mol=53.01\ mol$ The number of moles of solute: $0.125=(n)\div(n+53.01)$ $0.125n+6.626=n$ $n=7.57\ mol$ Mass of ethylene glycol: $7.57\ mol\times62.07\ g/mol=470.06\ g$ The molality of ethylene glycol: $7.57\ mol\div (955/1000)kg=7.9\ m$