Answer
C
Work Step by Step
$\Delta_{soln}H^{\circ}[LiOH]=\Delta_fH^{\circ}[LiOH(aq)]-\Delta_fH^{\circ}[LiOH(s)]$
$\Delta_{soln}H^{\circ}[LiOH]=-508.48-(-484.93)=-23.55\ kJ/mol$
Chemistry and Chemical Reactivity (9th Edition)
by Kotz, John C.; Treichel, Paul M.; Townsend, John R.; Treichel, David A.
Published by
Cengage Learning
ISBN 10:
1133949649
ISBN 13:
978-1-13394-964-0
Chapter 13 Solutions and Their Behavior - 13-2 The Solution Process - Review & Check for Section 13-2 - Page 479: 1
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