Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 12 The Solid State - Study Questions - Page 467c: 35


18260 kJ

Work Step by Step

Heating the liquid: $\Delta H=12\ kg\times 4.7\ kJ/kg.K\times (-33.3--50)\ K=941.88\ kJ$ Boiling: $\Delta H=12\ kg\times23.33\ kJ/mol\div 17.03\ g/mol\times1000\ g/kg=16439\ kJ$ Heating the gas: $\Delta H=12\ kg\times 2.2\ kJ/kg.K\times (0--33.3)\ K=879.12\ kJ$ Total heat required: 18260 kJ
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