# Chapter 12 The Solid State - 12-5 The Solid State: Other Types of Solid Materials - Case Study - Questions - Page 458: 2

4154 rings

#### Work Step by Step

From the previous answer, the side-to-side length of a ring is 240.76 pm so in 1.0 $\mu m$ there are: $1.0\mu m/240.76\times 10^{-6}\mu m=4154$ rings

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