Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 12 The Solid State - 12-2 Structures and Formulas of Ionic Solids - Case Study - Questions - Page 445: 3

Answer

$0.533\ g/cm^3$

Work Step by Step

For a body-centered cubic arrangement there are $8 \times 1/8$ atoms in the corners and one in the center, so 2 atoms per unit cell: Mass: $2\times 6.94\ g/mol\div 6.022\times 10^{23}\ atoms/mol=2.31\times10^{-23}\ g/cell$ Volume: $(351\times 10^{-10}\ cm)^3=4.32\times10^{-23}\ cm^3/cell$ Density: $2.31\times10^{-23}\ g/cell\div 4.32\times10^{-23}\ cm^3/cell=0.533\ g/cm^3$
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