Answer
See the answer below.
Work Step by Step
More polarizability implies stronger London Dispersion Forces since all of them are nonpolar. Polarizability has to do with the size of the electron cloud, so atoms with larger molecular weights are more polarizable and hence have stronger London Dispersion Forces. Thus, it follows:
$F_2\lt Cl_2\lt Br_2\lt I_2$
$Xe\lt Kr\lt Ar\lt Ne\lt He$
