See the answer below.
Work Step by Step
a) At 30$°C$, from the chart: 400 mmHg for $CS_2$ and 50 mmHg for $CH_3NO_2$ b) In $CS_2$, only London Dispersion interactions are present because it is nonpolar. $CH_3NO_2$ has dipole-dipole interactions because it is polar. c) The normal boiling point is the temperature at which the vapor pressure is equal to 760 mmHg so: $CS_2: 50°C,\ CH_3NO_2: 100°C$ d) From the chart: $40°C$ e) From the chart: $95°C$