Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 10 Gases and Their Properties - Study Questions - Page 403f: 77


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Work Step by Step

Number of moles of the gas: $n=PV/RT$ $n=(17.2/760×1\ atm)×1.85\ L/0.082/294\ K$ $n=1.74×10^{-3}\ mol$ Molecular weight: $0.150\ g\div 1.74×10^{-3}\ mol=86.4\ g/mol$ The most likely possibility is $ClO_2F$
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