## Chemistry and Chemical Reactivity (9th Edition)

Number of moles of the gas: $n=PV/RT$ $n=(17.2/760×1\ atm)×1.85\ L/0.082/294\ K$ $n=1.74×10^{-3}\ mol$ Molecular weight: $0.150\ g\div 1.74×10^{-3}\ mol=86.4\ g/mol$ The most likely possibility is $ClO_2F$