Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 10 Gases and Their Properties - 10-6 The Kinetic-Molecular Theory of Gases - Case Study - Questions - Page 394: 4


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Work Step by Step

Number of moles of air: $n=PV/RT$ $n=1.0\ atm×1\ km^3×1×10^{12}\ L/km^3/0.082057\ L.atm/mol.K/(25+273)\ K$ $n=4.09×10^{10}\ mol$ Number of moles of methane: $4.09×10^{10}\ mol_{air}×177.4\ mol_{CH_4}/10^9\ mol_{air}=7255\ mol$ A) Number of molecules: $7255\ mol×6.022×10^{23}\ molecules/mol=4.44×10^{27}\ molecules$ B) From stoichiometry, the number of moles of methane and methylphosphonate are the same: $7255\ mol×95.01\ g/mol=689.3\ kg$
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