Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 10 Gases and Their Properties - 10-2 Gas Laws: The Experimental Basis - Review & Check for Section 10-2 - Page 381: 2

Answer

D

Work Step by Step

Since the pressure is constant, we can use Charles' law: $235\ mL/(25+273)\ K=310\ mL/(x+273)\ K$ Solving for x: $x=120.11°C$
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