Answer
The final concentration of that $HCl$ solution is equal to 2.0 M
Work Step by Step
1. Write the dilution expression, and rearrange it to solve for "$C_2$":
$C_1V_1 = C_2V_2$
- Divide both sides by "$V_2$":
$\frac{C_1V_1}{V_2} = C_2$
$ C_2 = \frac{C_1V_1}{V_2}$
2. Substitute the given values, and calculate the value of the final concentration.
$ C_2 =\frac{(6.0 \space M)(2.0 \space L)}{6.0 \space L}$
$C_2 = 2.0 \space M$